# Sulvme!

### Solution to Unified Tertiary Matriculation Examination Mathematics 2011 No. 26

#### To find the inverse of a $2 \times 2$ matrix,We need to find the determinantFrom the above equation,$det = (2\times4) - (3 \times 1)$        =  8 - 3        = 5Now we find inverse of 5 which is$\frac{1}{5}$We now interchange the position of the values in the matrixInterchange a11 and a22, then negate the signs of a12 and a21Therefore, we now have$\frac{1}{5}\begin{bmatrix} 4 & -3\\ -1 & 2 \end{bmatrix}$

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